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zip_entry_open> <zip_entry_filesize
Last updated: Fri, 22 Aug 2008

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zip_entry_name

(PHP 4 >= 4.0.7, PHP 5 >= 5.2.0, PECL zip:1.0-1.9.0)

zip_entry_nameObtiene el nombre de una entrada de directorio

Descripción

string zip_entry_name ( resource $zip_entry )

Devuelve el nombre de la entrada de directorio indicada.

Lista de parámetros

zip_entry

Este parámetro debe ser una entrada de directorio válida obtenida mediante la función zip_read().

Valores retornados

Devuelve el nombre de la entrada de directorio.

Ver también



add a note add a note User Contributed Notes
zip_entry_name
leandro_dealmeida at hotmail dot com
27-Sep-2002 06:21
If you want to get the real name of the file without the directory name, you can just use the function basename() as the follow:

<?
$zip_dir
= "./import/";
$zip = zip_open($zip_dir."import.zip");
if (
$zip) {
    while (
$zip_entry = zip_read($zip)) {

       
$file = basename(zip_entry_name($zip_entry));
       
$fp = fopen($zip_dir.basename($file), "w+");
       
        if (
zip_entry_open($zip, $zip_entry, "r")) {
           
$buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
           
zip_entry_close($zip_entry);
        }
       
          
fwrite($fp, $buf);
       
fclose($fp);
       
        echo
"The file ".$file." was extracted to dir ".$zip_dir."\n<br>";
    }
   
zip_close($zip);
}
?>

Thefore you can extract files without concern with the directory that is set inside the zip source.

Remember to give write permission (w) on that directory.

Hello from Brazil.
Leandro

zip_entry_open> <zip_entry_filesize
Last updated: Fri, 22 Aug 2008
 
 
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